What is expand-3/4 (x+2)(x+1)(x-3) ?

The solution to expand-3/4 (x+2)(x+1)(x-3) is -(3x^3)/4+(21x)/4+9/2

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expand-3/4 (x+2)(x+1)(x-3)

expand

- \frac{3}{4} (x + 2) (x + 1) (x - 3)

- \frac{3 x ^{3}}{4} + \frac{21 x}{4} + \frac{9}{2}

Solution steps

- \frac{3}{4} (x + 2) (x + 1) (x - 3)

Expand

- \frac{3}{4} (x + 2) (x + 1) (x - 3) : - \frac{3}{4} (x^{2} + 3 x + 2) (x - 3)

= - \frac{3}{4} (x^{2} + 3 x + 2) (x - 3)

Expand

- \frac{3}{4} (x - 3) : - \frac{3 x}{4} + \frac{9}{4}

= (- \frac{3 x}{4} + \frac{9}{4}) (x^{2} + 3 x + 2)

Distribute parentheses

= - \frac{3 x}{4} x^{2} - \frac{3 x}{4} \cdot 3 x - \frac{3 x}{4} \cdot 2 + \frac{9}{4} x^{2} + \frac{9}{4} \cdot 3 x + \frac{9}{4} \cdot 2

Simplify

- \frac{3 x}{4} x^{2} - \frac{3 x}{4} \cdot 3 x - \frac{3 x}{4} \cdot 2 + \frac{9}{4} x^{2} + \frac{9}{4} \cdot 3 x + \frac{9}{4} \cdot 2 : - \frac{3 x ^{3}}{4} + \frac{21 x}{4} + \frac{9}{2}

= - \frac{3 x ^{3}}{4} + \frac{21 x}{4} + \frac{9}{2}

\frac{20 ( 5 + 2 5 )}{3}

\frac{200 - 200 ( 1 - x ) ^{\frac{1}{3}}}{( 1 - x ) ^{\frac{1}{3}}}

(\frac{2 i}{n} + 1)^{2}

\frac{( x + 3 ) ( x + 1 )}{x ^{2} + 1}

2 x l e f t (x^{2} - 3)

What is expand-3/4 (x+2)(x+1)(x-3) ?
The solution to expand-3/4 (x+2)(x+1)(x-3) is -(3x^3)/4+(21x)/4+9/2