What is 4x-3>9\lor-8x>= 16 ?

The solution to 4x-3>9\lor-8x>= 16 is x 3

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4x-3>9\lor-8x>= 16

4 x - 3 > 9 or - 8 x \geq 16

x \leq - 2 or x > 3

Solution steps

4 x - 3 > 9 or - 8 x \geq 16

4 x - 3 > 9 : x > 3

- 8 x \geq 16 : x \leq - 2

Combine the intervals

x > 3 or x \leq - 2

Merge Overlapping Intervals

x \leq - 2 or x > 3

- (\frac{27}{1})^{\frac{1}{3}}

∣ y - 3 ∣ = 2 y - 10

\frac{6 + 12 i}{3 i}

\frac{2}{3} (2)^{\frac{3}{2}}

x - 9 = \frac{3}{5} x

What is 4x-3>9\lor-8x>= 16 ?
The solution to 4x-3>9\lor-8x>= 16 is x<=-2\lor x>3