What is expand (x^2+2)cos(3x+4) ?

The solution to expand (x^2+2)cos(3x+4) is x^2cos(3x+4)+2cos(3x+4)

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expand (x^2+2)cos(3x+4)

expand

(x^{2} + 2) cos (3 x + 4)

x^{2} cos (3 x + 4) + 2 cos (3 x + 4)

Solution steps

(x^{2} + 2) cos (3 x + 4)

= cos (3 x + 4) (x^{2} + 2)

Apply the distributive law:

a (b + c) = ab + a c

cos (3 x + 4) (x^{2} + 2) = cos (3 x + 4) x^{2} + cos (3 x + 4) \cdot 2

= cos (3 x + 4) x^{2} + cos (3 x + 4) \cdot 2

= x^{2} cos (3 x + 4) + 2 cos (3 x + 4)

\frac{e ^{- 2 s} - 1}{s ( s + 1 )}

x^{6} + (y - 2)^{6}

\frac{36 ( x ^{2} - 42 x + 432 )}{π} - 1623

(e^{(- s t - 2 t)}) (cos (2 t) - 4 sin (2 t)) d t

\frac{d ^{2}}{d x ^{2}} ((y^{2}) (x^{2} - 2 x y + 3 y^{2} - 20 y))

What is expand (x^2+2)cos(3x+4) ?
The solution to expand (x^2+2)cos(3x+4) is x^2cos(3x+4)+2cos(3x+4)