What is expand ((x-5)(x+12))/((x+2)(x-4)) ?

The solution to expand ((x-5)(x+12))/((x+2)(x-4)) is (x^2+7x-60)/(x^2-2x-8)

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expand ((x-5)(x+12))/((x+2)(x-4))

expand

\frac{( x - 5 ) ( x + 12 )}{( x + 2 ) ( x - 4 )}

\frac{x ^{2} + 7 x - 60}{x ^{2} - 2 x - 8}

Solution steps

\frac{( x - 5 ) ( x + 12 )}{( x + 2 ) ( x - 4 )}

Expand

(x + 2) (x - 4) : x^{2} - 2 x - 8

= \frac{( x - 5 ) ( x + 12 )}{x ^{2} - 2 x - 8}

Expand

(x - 5) (x + 12) : x^{2} + 7 x - 60

= \frac{x ^{2} + 7 x - 60}{x ^{2} - 2 x - 8}

200 (8 - e^{- 0.1 x})

(x^{3} - \frac{1}{x})^{20}

(x - 5) (x + 4 - 3)

A (6 i - 2 j - 3 k) \times B (2 i - 4 j + 4 k)

\frac{( t ^{4} + 3 t ^{2} ) ^{2}}{9 ( t ^{2} + 1 ) ^{4}}

What is expand ((x-5)(x+12))/((x+2)(x-4)) ?
The solution to expand ((x-5)(x+12))/((x+2)(x-4)) is (x^2+7x-60)/(x^2-2x-8)