What is expand-8/(e^{2x)x}+1/(2(x-2)) ?

The solution to expand-8/(e^{2x)x}+1/(2(x-2)) is -8/(e^{2x)x}+1/(2x-4)

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expand-8/(e^{2x)x}+1/(2(x-2))

expand

- \frac{8}{e ^{2 x} x} + \frac{1}{2 ( x - 2 )}

- \frac{8}{e ^{2 x} x} + \frac{1}{2 x - 4}

Solution steps

- \frac{8}{e ^{2 x} x} + \frac{1}{2 ( x - 2 )}

Expand

2 (x - 2) : 2 x - 4

= - \frac{8}{e ^{2 x} x} + \frac{1}{2 x - 4}

\frac{2 ( 1 - 2 x ^{\frac{3}{2}} + x ^{3} )}{3}

(6 - 7 y)^{2}

(e^{x^{2}} - e^{- x^{2}})^{2}

(4 + 3 i)^{6}

(28500 + 1000 ln (\frac{33}{14})) (\frac{1}{57})

What is expand-8/(e^{2x)x}+1/(2(x-2)) ?
The solution to expand-8/(e^{2x)x}+1/(2(x-2)) is -8/(e^{2x)x}+1/(2x-4)