What is (\partial)/(\partial v)((x)(9u+2v)) ?

The answer to (\partial)/(\partial v)((x)(9u+2v)) is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial v)((x)(9u+2v))

\frac{\partial}{\partial v} ((x) (9 u + 2 v))

2 x

Solution steps

\frac{\partial}{\partial v} ((x) (9 u + 2 v))

Treat

x, u

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial v} (9 u + 2 v)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{\partial}{\partial v} (9 u) + \frac{\partial}{\partial v} (2 v))

\frac{\partial}{\partial v} (9 u) = 0

\frac{\partial}{\partial v} (2 v) = 2

= x (0 + 2)

Simplify

= 2 x

(x - 2) \cdot x \cdot (72 + 7 x)

\frac{3 y \cdot ( 6 - y - z ) ^{2}}{2}

(- 3, - 1, 1, 2) l e f t (- 1, 0, - 2, - 1)

Δ (3 x - 2)

x (1 + \frac{1}{x})

What is (\partial)/(\partial v)((x)(9u+2v)) ?
The answer to (\partial)/(\partial v)((x)(9u+2v)) is 2x