What is expand (10a(4x+9))/(81bx) ?

The solution to expand (10a(4x+9))/(81bx) is (40a)/(81b)+(10a)/(9bx)

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expand (10a(4x+9))/(81bx)

expand

\frac{10 a ( 4 x + 9 )}{81 b x}

\frac{40 a}{81 b} + \frac{10 a}{9 b x}

Solution steps

\frac{10 a ( 4 x + 9 )}{81 b x}

Expand

10 a (4 x + 9) : 40 a x + 90 a

= \frac{40 a x + 90 a}{81 b x}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{40 a x + 90 a}{81 b x} = \frac{40 a x}{81 b x} + \frac{90 a}{81 b x}

= \frac{40 a x}{81 b x} + \frac{90 a}{81 b x}

Cancel

\frac{40 a x}{81 b x} : \frac{40 a}{81 b}

= \frac{40 a}{81 b} + \frac{90 a}{81 b x}

Cancel

\frac{90 a}{81 b x} : \frac{10 a}{9 b x}

= \frac{40 a}{81 b} + \frac{10 a}{9 b x}

tan (x) (1 + sec (x))

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\frac{( x ^{2} - x + 4 )}{( x + 3 ) ( x - 1 ) ( x + 2 )}

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What is expand (10a(4x+9))/(81bx) ?
The solution to expand (10a(4x+9))/(81bx) is (40a)/(81b)+(10a)/(9bx)