What is (2+sin(θ))^2+cos^2(θ) ?

The solution to (2+sin(θ))^2+cos^2(θ) is 4sin(θ)+5

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simplify (2+sin(θ))^2+cos^2(θ)

simplify

(2 + sin (θ))^{2} + cos^{2} (θ)

4 sin (θ) + 5

Solution steps

(2 + sin (θ))^{2} + cos^{2} (θ)

Expand

(2 + sin (θ))^{2} : 4 + 4 sin (θ) + sin^{2} (θ)

= 4 + 4 sin (θ) + sin^{2} (θ) + cos^{2} (θ)

Use the Pythagorean identity:

cos^{2} (x) + sin^{2} (x) = 1

= 4 sin (θ) + 4 + 1

Add the numbers:

4 + 1 = 5

= 4 sin (θ) + 5

(3 - \frac{3}{2 y})^{2}

(10 b - \frac{4}{3} y)^{2}

4 (e^{x} + e^{x} x)

5 (\frac{3}{7} u - \frac{3}{13} v^{2})^{2}

\frac{( 3 + 4 x ) ^{3}}{( 4 - 3 x ) ^{4}}

What is (2+sin(θ))^2+cos^2(θ) ?
The solution to (2+sin(θ))^2+cos^2(θ) is 4sin(θ)+5