What is expand ((k+2)(2k+3)(2k+5))/3 ?

The solution to expand ((k+2)(2k+3)(2k+5))/3 is (4k^3)/3+8k^2+(47k)/3+10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((k+2)(2k+3)(2k+5))/3

expand

\frac{( k + 2 ) ( 2 k + 3 ) ( 2 k + 5 )}{3}

\frac{4 k ^{3}}{3} + 8 k^{2} + \frac{47 k}{3} + 10

Solution steps

\frac{( k + 2 ) ( 2 k + 3 ) ( 2 k + 5 )}{3}

Expand

(k + 2) (2 k + 3) (2 k + 5) : 4 k^{3} + 24 k^{2} + 47 k + 30

= \frac{4 k ^{3} + 24 k ^{2} + 47 k + 30}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{4 k ^{3} + 24 k ^{2} + 47 k + 30}{3} = \frac{4 k ^{3}}{3} + \frac{24 k ^{2}}{3} + \frac{47 k}{3} + \frac{30}{3}

= \frac{4 k ^{3}}{3} + \frac{24 k ^{2}}{3} + \frac{47 k}{3} + \frac{30}{3}

Divide the numbers:

\frac{24}{3} = 8

= \frac{4 k ^{3}}{3} + 8 k^{2} + \frac{47 k}{3} + \frac{30}{3}

Divide the numbers:

\frac{30}{3} = 10

= \frac{4 k ^{3}}{3} + 8 k^{2} + \frac{47 k}{3} + 10

\frac{( n + 1 ) ( n + 2 )}{( n + 2 ) !}

\frac{- 10 ( x + 3 ) ^{\frac{3}{2}} + 2 ( x + 3 ) ^{\frac{5}{2}}}{5}

\frac{1}{2} (- 2 x + 2) + 2

\frac{500 k}{( s ^{2} + 25 s + 100 k ) ( s ^{2} + 1 )}

7 (5 + 11)

What is expand ((k+2)(2k+3)(2k+5))/3 ?
The solution to expand ((k+2)(2k+3)(2k+5))/3 is (4k^3)/3+8k^2+(47k)/3+10