What is expand-(2x+h)/((x^2-4)((x+h)^2-4)) ?

The solution to expand-(2x+h)/((x^2-4)((x+h)^2-4)) is -(2x+h)/(x^4+2x^3h+x^2h^2-8x^2-8xh-4h^2+16)

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expand-(2x+h)/((x^2-4)((x+h)^2-4))

expand

- \frac{2 x + h}{( x ^{2} - 4 ) ( ( x + h ) ^{2} - 4 )}

- \frac{2 x + h}{x ^{4} + 2 x ^{3} h + x ^{2} h ^{2} - 8 x ^{2} - 8 x h - 4 h ^{2} + 16}

Solution steps

- \frac{2 x + h}{( x ^{2} - 4 ) ( ( x + h ) ^{2} - 4 )}

Expand

(x + h)^{2} - 4 : x^{2} + 2 x h + h^{2} - 4

= - \frac{2 x + h}{( x ^{2} - 4 ) ( x ^{2} + 2 x h + h ^{2} - 4 )}

Expand

(x^{2} - 4) (x^{2} + 2 x h + h^{2} - 4) : x^{4} + 2 x^{3} h + x^{2} h^{2} - 8 x^{2} - 8 x h - 4 h^{2} + 16

= - \frac{2 x + h}{x ^{4} + 2 x ^{3} h + x ^{2} h ^{2} - 8 x ^{2} - 8 x h + 16 - 4 h ^{2}}

- 5 (x + Δ x)^{4}

(- 5, 1 - 65) (- 5, 8) y (- 5, - 6)

A (- \frac{1}{2}, 3) y B (4, - \frac{2}{3})

(x - \frac{7}{2}) (x + \frac{7}{3})

(16 - y) (\frac{y}{2} + 15)

What is expand-(2x+h)/((x^2-4)((x+h)^2-4)) ?
The solution to expand-(2x+h)/((x^2-4)((x+h)^2-4)) is -(2x+h)/(x^4+2x^3h+x^2h^2-8x^2-8xh-4h^2+16)