What is expand (y^2-9)(y^2-9)' ?

The solution to expand (y^2-9)(y^2-9)' is (y^2-9)'y^2-9(y^2-9)'

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expand (y^2-9)(y^2-9)'

expand

(y^{2} - 9) (y^{2} - 9)^{'}

(y^{2} - 9)' y^{2} - 9 (y^{2} - 9)'

Solution steps

(y^{2} - 9) (y^{2} - 9)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (y^{2} - 9)^{'}, b = y^{2}, c = 9

= (y^{2} - 9)^{^{'}} y^{2} - (y^{2} - 9)^{^{'}} 9

= (y^{2} - 9)^{^{'}} y^{2} - 9 (y^{2} - 9)^{^{'}}

(s + 4) (s + \frac{1}{2}) (s + \frac{6}{5}) (s + \frac{5}{2})

(e^{2 x} - 5 e^{x} + 6 = 1) e^{x}

\frac{( x ^{2} + 1 ) ( x ^{2} - x + 1 )}{x ( x ^{2} + 2 )}

\frac{s ^{3} ( 5 t ^{2} - 6 t + 3 H ( t ) - 3 e ^{- 2 t} )}{3 ( s + 2 )}

2 (π - 2)

What is expand (y^2-9)(y^2-9)' ?
The solution to expand (y^2-9)(y^2-9)' is (y^2-9)'y^2-9(y^2-9)'