What is expand 1/(s(s+3)(s+1)) ?

The solution to expand 1/(s(s+3)(s+1)) is 1/(s^3+4s^2+3s)

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expand 1/(s(s+3)(s+1))

expand

\frac{1}{s ( s + 3 ) ( s + 1 )}

\frac{1}{s ^{3} + 4 s ^{2} + 3 s}

Solution steps

\frac{1}{s ( s + 3 ) ( s + 1 )}

Expand

s (s + 3) (s + 1) : s^{3} + 4 s^{2} + 3 s

= \frac{1}{s ^{3} + 4 s ^{2} + 3 s}

4 (16 - 3 π) c m^{2}

(x + 2) (x - 2) [x - \frac{2}{x ^{2} - 4} + \frac{1}{x + 2} = \frac{1}{x - 2}]

(x - 9) x

\frac{( 2 x + 1 ) ^{3} ( 2 x - 3 ) ^{3}}{x ^{6}}

(- 1, 3) y (3, - 8) p u n t o (9, 6)

What is expand 1/(s(s+3)(s+1)) ?
The solution to expand 1/(s(s+3)(s+1)) is 1/(s^3+4s^2+3s)