What is expand e^{e^x+x}(e^x+1) ?

The solution to expand e^{e^x+x}(e^x+1) is e^{2x+e^x}+e^{e^x+x}

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expand e^{e^x+x}(e^x+1)

expand

e^{e^{x} + x} (e^{x} + 1)

e^{2 x + e^{x}} + e^{e^{x} + x}

Solution steps

e^{e^{x} + x} (e^{x} + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = e^{e^{x} + x}, b = e^{x}, c = 1

= e^{e^{x} + x} e^{x} + e^{e^{x} + x} \cdot 1

= e^{x} e^{e^{x} + x} + 1 \cdot e^{e^{x} + x}

Simplify

e^{x} e^{e^{x} + x} + 1 \cdot e^{e^{x} + x} : e^{2 x + e^{x}} + e^{e^{x} + x}

= e^{2 x + e^{x}} + e^{e^{x} + x}

\frac{( 2 n + 1 ) x ^{2 n}}{( 2 n + 1 ) !}

\frac{e ^{x}}{( e ^{x} - e ^{2} ) ^{2}}

\frac{1}{( 1 - i w ) ^{2}}

e^{π 2 (1 + i)}

What is expand e^{e^x+x}(e^x+1) ?
The solution to expand e^{e^x+x}(e^x+1) is e^{2x+e^x}+e^{e^x+x}