What is expand (e^{x/2})(x+1) ?

The solution to expand (e^{x/2})(x+1) is e^{x/2}x+e^{x/2}

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expand (e^{x/2})(x+1)

expand

(e^{\frac{x}{2}}) (x + 1)

e^{\frac{x}{2}} x + e^{\frac{x}{2}}

Solution steps

(e^{\frac{x}{2}}) (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = (e^{\frac{x}{2}}), b = x, c = 1

= (e^{\frac{x}{2}}) x + (e^{\frac{x}{2}}) \cdot 1

= x (e^{\frac{x}{2}}) + 1 \cdot (e^{\frac{x}{2}})

Simplify

x (e^{\frac{x}{2}}) + 1 \cdot (e^{\frac{x}{2}}) : e^{\frac{x}{2}} x + e^{\frac{x}{2}}

= e^{\frac{x}{2}} x + e^{\frac{x}{2}}

x lo g_{10} (4)

(x + \frac{1}{12}) (x - 9)

\frac{- x ^{2} + a ^{2}}{( x ^{2} + a ^{2} ) ^{2}}

(\frac{1}{2} + \frac{1}{2} cos (6 x))^{4}

sin (\frac{11 π}{60} + \frac{7 π}{30})

What is expand (e^{x/2})(x+1) ?
The solution to expand (e^{x/2})(x+1) is e^{x/2}x+e^{x/2}