What is 1/2 (θ+1/2 sin(2θ)) ?

The solution to 1/2 (θ+1/2 sin(2θ)) is (θ+1/2 sin(2θ))/2

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simplify 1/2 (θ+1/2 sin(2θ))

simplify

\frac{1}{2} (θ + \frac{1}{2} sin (2 θ))

\frac{θ + \frac{1}{2} sin ( 2 θ )}{2}

Solution steps

\frac{1}{2} (θ + \frac{1}{2} sin (2 θ))

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( θ + \frac{1}{2} sin ( 2 θ ) )}{2}

Apply rule:

1 \cdot a = a

1 \cdot (θ + \frac{1}{2} sin (2 θ)) = (θ + \frac{1}{2} sin (2 θ))

= \frac{θ + \frac{1}{2} sin ( 2 θ )}{2}

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2 e^{3 - t} + t^{3} + (t + 1)^{2}

\frac{3 x ^{4} - 10 x ^{3} + 2 x ^{2} - 3 x + 5}{( x - 1 ) ( 3 x + 1 )}

What is 1/2 (θ+1/2 sin(2θ)) ?
The solution to 1/2 (θ+1/2 sin(2θ)) is (θ+1/2 sin(2θ))/2