What is expand (2(x^2-4))/(x^2-9) ?

The solution to expand (2(x^2-4))/(x^2-9) is (2x^2-8)/(x^2-9)

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expand (2(x^2-4))/(x^2-9)

expand

\frac{2 ( x ^{2} - 4 )}{x ^{2} - 9}

\frac{2 x ^{2} - 8}{x ^{2} - 9}

Solution steps

\frac{2 ( x ^{2} - 4 )}{x ^{2} - 9}

Expand

2 (x^{2} - 4) : 2 x^{2} - 8

= \frac{2 x ^{2} - 8}{x ^{2} - 9}

(4 tan (x) + 3)^{2}

\frac{( m - 3 ) ( m + 5 )}{m - 25}

\frac{( z + 1 ) z}{3 ( z ^{2} - z + 1 )}

csc^{2} (x) (sec^{2} (x) - cos^{2} (x))

\frac{- 2 e ^{\frac{1}{x}} + x ( 2 e ^{\frac{1}{x}} - 2 )}{3 x}

What is expand (2(x^2-4))/(x^2-9) ?
The solution to expand (2(x^2-4))/(x^2-9) is (2x^2-8)/(x^2-9)