What is expand 3e^{3x}x^3ln(x+1)(x+1) ?

The solution to expand 3e^{3x}x^3ln(x+1)(x+1) is 3e^{3x}x^4ln(x+1)+3e^{3x}x^3ln(x+1)

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expand 3e^{3x}x^3ln(x+1)(x+1)

expand

3 e^{3 x} x^{3} ln (x + 1) (x + 1)

3 e^{3 x} x^{4} ln (x + 1) + 3 e^{3 x} x^{3} ln (x + 1)

Solution steps

3 e^{3 x} x^{3} ln (x + 1) (x + 1)

Apply the distributive law:

a (b + c) = ab + a c

a = 3 e^{3 x} x^{3} ln (x + 1), b = x, c = 1

= 3 e^{3 x} x^{3} ln (x + 1) x + 3 e^{3 x} x^{3} ln (x + 1) \cdot 1

= 3 e^{3 x} x^{3} x ln (x + 1) + 3 \cdot 1 \cdot e^{3 x} x^{3} ln (x + 1)

Simplify

3 e^{3 x} x^{3} x ln (x + 1) + 3 \cdot 1 \cdot e^{3 x} x^{3} ln (x + 1) : 3 e^{3 x} x^{4} ln (x + 1) + 3 e^{3 x} x^{3} ln (x + 1)

= 3 e^{3 x} x^{4} ln (x + 1) + 3 e^{3 x} x^{3} ln (x + 1)

- 3 (x - 1 = - 4) x + 20

(- 1 - 37)^{3}

(x - 1) \cdot x^{\frac{x}{2}}

\frac{d ^{2}}{d x ^{2}} ((y) (3 x - y + 3))

\frac{1}{S ( S ^{2} + 0.2 S + 1 )}

What is expand 3e^{3x}x^3ln(x+1)(x+1) ?
The solution to expand 3e^{3x}x^3ln(x+1)(x+1) is 3e^{3x}x^4ln(x+1)+3e^{3x}x^3ln(x+1)