What is expand (((2x+8))/6)^3 ?

The solution to expand (((2x+8))/6)^3 is (x^3}{27}+\frac{4x^2)/9+(16x)/9+64/27

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expand (((2x+8))/6)^3

expand

(\frac{( 2 x + 8 )}{6})^{3}

\frac{x ^{3}}{27} + \frac{4 x ^{2}}{9} + \frac{16 x}{9} + \frac{64}{27}

Solution steps

(\frac{2 x + 8}{6})^{3}

\frac{2 x + 8}{6} = \frac{x + 4}{3}

= (\frac{x + 4}{3})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( x + 4 ) ^{3}}{3 ^{3}}

(x + 4)^{3} = x^{3} + 12 x^{2} + 48 x + 64

= \frac{x ^{3} + 12 x ^{2} + 48 x + 64}{3 ^{3}}

3^{3} = 27

= \frac{x ^{3} + 12 x ^{2} + 48 x + 64}{27}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{3} + 12 x ^{2} + 48 x + 64}{27} = \frac{x ^{3}}{27} + \frac{12 x ^{2}}{27} + \frac{48 x}{27} + \frac{64}{27}

= \frac{x ^{3}}{27} + \frac{12 x ^{2}}{27} + \frac{48 x}{27} + \frac{64}{27}

Cancel

\frac{12 x ^{2}}{27} : \frac{4 x ^{2}}{9}

= \frac{x ^{3}}{27} + \frac{4 x ^{2}}{9} + \frac{48 x}{27} + \frac{64}{27}

Cancel

\frac{48 x}{27} : \frac{16 x}{9}

= \frac{x ^{3}}{27} + \frac{4 x ^{2}}{9} + \frac{16 x}{9} + \frac{64}{27}

\frac{1296 ( e - 1 )}{49}

72 (\frac{7 π}{6} + \frac{1}{4})

\frac{( x + h ) ^{2} + 7 - x ^{2} + 7}{h}

\frac{2 x + 1}{4 ( x ^{2} + x ) ^{\frac{5}{4}}}

(- 67 y - 97)^{2}

What is expand (((2x+8))/6)^3 ?
The solution to expand (((2x+8))/6)^3 is (x^3}{27}+\frac{4x^2)/9+(16x)/9+64/27