What is expand 3-sin(2x^2-3x-1)(4x-3) ?

The solution to expand 3-sin(2x^2-3x-1)(4x-3) is 3-4xsin(2x^2-3x-1)+3sin(2x^2-3x-1)

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expand 3-sin(2x^2-3x-1)(4x-3)

expand

3 - sin (2 x^{2} - 3 x - 1) (4 x - 3)

3 - 4 x sin (2 x^{2} - 3 x - 1) + 3 sin (2 x^{2} - 3 x - 1)

Solution steps

3 - sin (2 x^{2} - 3 x - 1) (4 x - 3)

Apply the distributive law:

a (b - c) = ab - a c

- sin (2 x^{2} - 3 x - 1) (4 x - 3) = - sin (2 x^{2} - 3 x - 1) \cdot 4 x - (- sin (2 x^{2} - 3 x - 1)) \cdot 3

= 3 - sin (2 x^{2} - 3 x - 1) \cdot 4 x - (- sin (2 x^{2} - 3 x - 1)) \cdot 3

Simplify

- sin (2 x^{2} - 3 x - 1) \cdot 4 x - (- sin (2 x^{2} - 3 x - 1)) \cdot 3 : - 4 x sin (2 x^{2} - 3 x - 1) + 3 sin (2 x^{2} - 3 x - 1)

= 3 - 4 x sin (2 x^{2} - 3 x - 1) + 3 sin (2 x^{2} - 3 x - 1)

(3 x^{2} + 3 y^{2} \frac{d y}{d x}) (x^{2} + y^{2})

\frac{2 ( 2 n + 3 ) \cdot ( 5 n + 3 )}{3 ( 5 n + 8 ) \cdot ( 2 n + 1 )}

f (x) (sin (\frac{x}{2}) = 2 + cos (x))

x + 8 x + 16

(cos (x) + a sin (x))^{2}

What is expand 3-sin(2x^2-3x-1)(4x-3) ?
The solution to expand 3-sin(2x^2-3x-1)(4x-3) is 3-4xsin(2x^2-3x-1)+3sin(2x^2-3x-1)