What is expand (2x)/((x^2-3)^2) ?

The solution to expand (2x)/((x^2-3)^2) is (2x)/(x^4-6x^2+9)

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expand (2x)/((x^2-3)^2)

expand

\frac{2 x}{( x ^{2} - 3 ) ^{2}}

\frac{2 x}{x ^{4} - 6 x ^{2} + 9}

Solution steps

\frac{2 x}{( x ^{2} - 3 ) ^{2}}

(x^{2} - 3)^{2} = x^{4} - 6 x^{2} + 9

= \frac{2 x}{x ^{4} - 6 x ^{2} + 9}

\frac{( 2 ^{t} )}{( t + 1 ) ( t - 1 )}

\frac{0.8 ( s - 1 )}{( s + 1 ) ( 0.3 s + 1 )}

cos^{2} (A) (1 + 2 tan (A)) + sin^{2} (A)

x^{\frac{1}{4}} (3 x - 3)

\frac{( \frac{7}{9} ( 3 x sin ( 3 x ) + cos ( 3 x ) ) + C )}{x}

What is expand (2x)/((x^2-3)^2) ?
The solution to expand (2x)/((x^2-3)^2) is (2x)/(x^4-6x^2+9)