What is expand x(2log_{10}(x)+1) ?

The solution to expand x(2log_{10}(x)+1) is 2xlog_{10}(x)+x

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expand x(2log_{10}(x)+1)

expand

x (2 lo g_{10} (x) + 1)

2 x lo g_{10} (x) + x

Solution steps

x (2 lo g_{10} (x) + 1)

Apply the distributive law:

a (b + c) = ab + a c

x (2 lo g_{10} (x) + 1) = x \cdot 2 lo g_{10} (x) + x \cdot 1

= x \cdot 2 lo g_{10} (x) + x \cdot 1

Simplify

x \cdot 2 lo g_{10} (x) + x \cdot 1 : 2 x lo g_{10} (x) + x

= 2 x lo g_{10} (x) + x

- 4 (m + 6 = - 8)

\frac{2 x ^{2} - 4 x + 9}{( 2 - x ) ( x + 3 )}

((y + x y^{3}) d x + x d y = 0) \frac{3}{y}

A (3, - 3) y B (- 1, - 1)

(- 3 - 4 i)^{6}

What is expand x(2log_{10}(x)+1) ?
The solution to expand x(2log_{10}(x)+1) is 2xlog_{10}(x)+x