What is expand t(1-(t+1)e-t) ?

The solution to expand t(1-(t+1)e-t) is t-et^2-et-t^2

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expand t(1-(t+1)e-t)

expand

t (1 - (t + 1) e - t)

t - e t^{2} - e t - t^{2}

Solution steps

t (1 - (t + 1) e - t)

= t (1 - e (t + 1) - t)

Distribute parentheses

= t \cdot 1 + t (- (t + 1) e) + t (- t)

Apply minus-plus rules

+ (- a) = - a

= 1 \cdot t - e t (t + 1) - tt

Simplify

1 \cdot t - e t (t + 1) - tt : t - e t^{2} - e t - t^{2}

= t - e t^{2} - e t - t^{2}

\frac{5}{( 5 x + 4 ) ^{2}}

20000 (1 - e^{- 0.05 t})^{2}

A (- 1, - 3) B (0, - 1) C (1, 1)

s (1 + \frac{s}{50})

What is expand t(1-(t+1)e-t) ?
The solution to expand t(1-(t+1)e-t) is t-et^2-et-t^2