What is expand x^{5/3}(x^{1/3}-x^{2/5}) ?

The solution to expand x^{5/3}(x^{1/3}-x^{2/5}) is x^2-x^{31/15}

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expand x^{5/3}(x^{1/3}-x^{2/5})

expand

x^{\frac{5}{3}} (x^{\frac{1}{3}} - x^{\frac{2}{5}})

x^{2} - x^{\frac{31}{15}}

Solution steps

x^{\frac{5}{3}} (x^{\frac{1}{3}} - x^{\frac{2}{5}})

Apply the distributive law:

a (b - c) = ab - a c

x^{\frac{5}{3}} (x^{\frac{1}{3}} - x^{\frac{2}{5}}) = x^{\frac{5}{3}} x^{\frac{1}{3}} - x^{\frac{5}{3}} x^{\frac{2}{5}}

= x^{\frac{5}{3}} x^{\frac{1}{3}} - x^{\frac{5}{3}} x^{\frac{2}{5}}

x^{\frac{5}{3}} x^{\frac{1}{3}} = x^{2}

x^{\frac{5}{3}} x^{\frac{2}{5}} = x^{\frac{31}{15}}

= x^{2} - x^{\frac{31}{15}}

\frac{1}{x ( 1 + ln ( x ) )}

x (1 + ln (x))

x^{(a + 1) \cdot 2}

4 + 5

What is expand x^{5/3}(x^{1/3}-x^{2/5}) ?
The solution to expand x^{5/3}(x^{1/3}-x^{2/5}) is x^2-x^{31/15}