What is expand (4+4sin(θ))*4cos(θ) ?

The solution to expand (4+4sin(θ))*4cos(θ) is 16cos(θ)+16cos(θ)sin(θ)

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expand (4+4sin(θ))*4cos(θ)

expand

(4 + 4 sin (θ)) \cdot 4 cos (θ)

16 cos (θ) + 16 cos (θ) sin (θ)

Solution steps

(4 + 4 sin (θ)) \cdot 4 cos (θ)

= 4 cos (θ) (4 + 4 sin (θ))

Apply the distributive law:

a (b + c) = ab + a c

4 cos (θ) (4 + 4 sin (θ)) = 4 cos (θ) \cdot 4 + 4 cos (θ) \cdot 4 sin (θ)

= 4 cos (θ) \cdot 4 + 4 cos (θ) \cdot 4 sin (θ)

Simplify

4 cos (θ) \cdot 4 + 4 cos (θ) \cdot 4 sin (θ) : 16 cos (θ) + 16 cos (θ) sin (θ)

= 16 cos (θ) + 16 cos (θ) sin (θ)

\frac{12 t ^{2} ( 5 - t )}{625}

((4 x - x^{2}), (4 - x)^{2}) \cdot (- 1, 4 - 2 x)

(x + 35) (x - 35)

(1 + i)^{10}

What is expand (4+4sin(θ))*4cos(θ) ?
The solution to expand (4+4sin(θ))*4cos(θ) is 16cos(θ)+16cos(θ)sin(θ)