What is 1/2 (8+log_{2}(3)) ?

The solution to 1/2 (8+log_{2}(3)) is 4+1/2 log_{2}(3)

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simplify 1/2 (8+log_{2}(3))

simplify

\frac{1}{2} (8 + lo g_{2} (3))

4 + \frac{1}{2} lo g_{2} (3)

Decimal Notation

4.79248 \dots

Solution steps

\frac{1}{2} (8 + lo g_{2} (3))

Apply the distributive law:

a (b + c) = ab + a c

\frac{1}{2} (8 + lo g_{2} (3)) = \frac{1}{2} \cdot 8 + \frac{1}{2} lo g_{2} (3)

= \frac{1}{2} \cdot 8 + \frac{1}{2} lo g_{2} (3)

\frac{1}{2} \cdot 8 = 4

= 4 + \frac{1}{2} lo g_{2} (3)

(4 sin (x) + 3) (sin (x) - 1)

(cos (θ) + 0.35)^{2}

\frac{3 x - 9}{( x ^{3} - 1 ) ( x - 2 ) ^{3} ( x ^{2} + x + 1 )}

\frac{2 x ( x - 3 )}{x ^{3} - x ^{2} - 6}

\frac{1}{( x + 5 ) ( x + 4 )}

What is 1/2 (8+log_{2}(3)) ?
The solution to 1/2 (8+log_{2}(3)) is 4+1/2 log_{2}(3)