What is expand ((x-4)(x+1))/((x+3)(x+2)) ?

The solution to expand ((x-4)(x+1))/((x+3)(x+2)) is (x^2-3x-4)/(x^2+5x+6)

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expand ((x-4)(x+1))/((x+3)(x+2))

expand

\frac{( x - 4 ) ( x + 1 )}{( x + 3 ) ( x + 2 )}

\frac{x ^{2} - 3 x - 4}{x ^{2} + 5 x + 6}

Solution steps

\frac{( x - 4 ) ( x + 1 )}{( x + 3 ) ( x + 2 )}

Expand

(x + 3) (x + 2) : x^{2} + 5 x + 6

= \frac{( x - 4 ) ( x + 1 )}{x ^{2} + 5 x + 6}

Expand

(x - 4) (x + 1) : x^{2} - 3 x - 4

= \frac{x ^{2} - 3 x - 4}{x ^{2} + 5 x + 6}

lo g_{10} (1 s)

(9 i, - 2 j, - 3 k) (i, - 6 j - 8 k)

\frac{1}{( 1 - x ) ( 1 + x ^{2} )}

(\frac{2 x}{3} + \frac{16}{3} = \frac{4 x}{2}) 6

\frac{12 e ^{- 2 x}}{( 1 + e ^{- 2 x} ) ^{2}}

What is expand ((x-4)(x+1))/((x+3)(x+2)) ?
The solution to expand ((x-4)(x+1))/((x+3)(x+2)) is (x^2-3x-4)/(x^2+5x+6)