What is expand ((x+3)(x-4))/(x+2) ?

The solution to expand ((x+3)(x-4))/(x+2) is (x^2-x-12)/(x+2)

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expand ((x+3)(x-4))/(x+2)

expand

\frac{( x + 3 ) ( x - 4 )}{x + 2}

\frac{x ^{2} - x - 12}{x + 2}

Solution steps

\frac{( x + 3 ) ( x - 4 )}{x + 2}

Expand

(x + 3) (x - 4) : x^{2} - x - 12

= \frac{x ^{2} - x - 12}{x + 2}

3 (6 + 63)

2 ((ln (\frac{5}{2})) - (ln (\frac{3}{2})))

4 \times 5

(\frac{4}{5} - 3 x) \cdot (\frac{4}{5} + 3 x)

- \frac{x ( x + 1 ) ( x + 10 )}{x + 5}

What is expand ((x+3)(x-4))/(x+2) ?
The solution to expand ((x+3)(x-4))/(x+2) is (x^2-x-12)/(x+2)