What is expand ((x-3)^2)/3 ?

The solution to expand ((x-3)^2)/3 is (x^2)/3-2x+3

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expand ((x-3)^2)/3

expand

\frac{( x - 3 ) ^{2}}{3}

\frac{x ^{2}}{3} - 2 x + 3

Solution steps

\frac{( x - 3 ) ^{2}}{3}

(x - 3)^{2} = x^{2} - 6 x + 9

= \frac{x ^{2} - 6 x + 9}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{2} - 6 x + 9}{3} = \frac{x ^{2}}{3} - \frac{6 x}{3} + \frac{9}{3}

= \frac{x ^{2}}{3} - \frac{6 x}{3} + \frac{9}{3}

Divide the numbers:

\frac{6}{3} = 2

= \frac{x ^{2}}{3} - 2 x + \frac{9}{3}

Divide the numbers:

\frac{9}{3} = 3

= \frac{x ^{2}}{3} - 2 x + 3

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