What is expand (3x+2)/((x-3)(x+2)) ?

The solution to expand (3x+2)/((x-3)(x+2)) is (3x+2)/(x^2-x-6)

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expand (3x+2)/((x-3)(x+2))

expand

\frac{3 x + 2}{( x - 3 ) ( x + 2 )}

\frac{3 x + 2}{x ^{2} - x - 6}

Solution steps

\frac{3 x + 2}{( x - 3 ) ( x + 2 )}

Expand

(x - 3) (x + 2) : x^{2} - x - 6

= \frac{3 x + 2}{x ^{2} - x - 6}

\frac{- 1 + ( 2 - 1 ) ln ( 2 + 1 )}{2}

\frac{3 x}{2} + \frac{x}{2}

8 a - (5 a = 8 - 2 (a - 3))

(2 x + 2) (2 x - 2)

\frac{3 ( ln ( 6 ) ) ^{n}}{n !}

What is expand (3x+2)/((x-3)(x+2)) ?
The solution to expand (3x+2)/((x-3)(x+2)) is (3x+2)/(x^2-x-6)