What is expand-(2(-(-1)^n+1))/(pin) ?

The solution to expand-(2(-(-1)^n+1))/(pin) is (2(-1)^n)/(pin)-2/(pin)

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expand-(2(-(-1)^n+1))/(pin)

expand

- \frac{2 ( - ( - 1 ) ^{n} + 1 )}{πn}

\frac{2 ( - 1 ) ^{n}}{πn} - \frac{2}{πn}

Solution steps

- \frac{2 ( - ( - 1 ) ^{n} + 1 )}{πn}

Expand

2 (- (- 1)^{n} + 1) : - 2 (- 1)^{n} + 2

= - \frac{2 - 2 ( - 1 ) ^{n}}{πn}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- 2 ( - 1 ) ^{n} + 2}{πn} = - (- \frac{2 ( - 1 ) ^{n}}{πn}) - (\frac{2}{πn})

= - (- \frac{2 ( - 1 ) ^{n}}{πn}) - (\frac{2}{πn})

Remove parentheses:

(a) = a, - (- a) = a

= \frac{2 ( - 1 ) ^{n}}{πn} - \frac{2}{πn}

\frac{x + 4}{2 + x - 6} + \frac{x - 3}{2 + 7 x + 12}

(x + \frac{4}{3})^{2}

(3 x - 9 x^{2} - 6 x + 3) (\frac{1}{x})

(c = \frac{- y}{x} + x^{2}) x

(- 2.5099 + 6.2121 i)^{5}

What is expand-(2(-(-1)^n+1))/(pin) ?
The solution to expand-(2(-(-1)^n+1))/(pin) is (2(-1)^n)/(pin)-2/(pin)