What is expand (-3x^2+2x+3)/(2(x+1)(x-1)) ?

The solution to expand (-3x^2+2x+3)/(2(x+1)(x-1)) is (-3x^2+2x+3)/(2x^2-2)

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expand (-3x^2+2x+3)/(2(x+1)(x-1))

expand

\frac{- 3 x ^{2} + 2 x + 3}{2 ( x + 1 ) ( x - 1 )}

\frac{- 3 x ^{2} + 2 x + 3}{2 x ^{2} - 2}

Solution steps

\frac{- 3 x ^{2} + 2 x + 3}{2 ( x + 1 ) ( x - 1 )}

Expand

2 (x + 1) (x - 1) : 2 x^{2} - 2

= \frac{- 3 x ^{2} + 2 x + 3}{2 x ^{2} - 2}

\frac{( x + 1 ) ^{2}}{( x + 3 ) ( x + 2 )}

e^{t} (t^{2} - 2 t - 2)

(\frac{s}{s ^{2} - 1}) (\frac{1}{s ^{2} + 1})

cos (2 (t + π))

e^{t} U (t - 4)

What is expand (-3x^2+2x+3)/(2(x+1)(x-1)) ?
The solution to expand (-3x^2+2x+3)/(2(x+1)(x-1)) is (-3x^2+2x+3)/(2x^2-2)