What is expand (sin(x))/((x-1)(x+1)^2) ?

The solution to expand (sin(x))/((x-1)(x+1)^2) is (sin(x))/(x^3+x^2-x-1)

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expand (sin(x))/((x-1)(x+1)^2)

expand

\frac{sin ( x )}{( x - 1 ) ( x + 1 ) ^{2}}

\frac{sin ( x )}{x ^{3} + x ^{2} - x - 1}

Solution steps

\frac{sin ( x )}{( x - 1 ) ( x + 1 ) ^{2}}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{sin ( x )}{( x - 1 ) ( x ^{2} + 2 x + 1 )}

Expand

(x - 1) (x^{2} + 2 x + 1) : x^{3} + x^{2} - x - 1

= \frac{sin ( x )}{x ^{3} + x ^{2} - x - 1}

- 1.8

lo g_{10} (x) (3 x - 4)

v (0, 0) f (0, - 3)

\frac{- 6 x ^{4} + 2}{( x ^{4} + 1 ) ^{2}}

(cos (θ) + tan (θ)) sin (θ)

What is expand (sin(x))/((x-1)(x+1)^2) ?
The solution to expand (sin(x))/((x-1)(x+1)^2) is (sin(x))/(x^3+x^2-x-1)