What is expand ((-10/5 x^4y^3z^2))/((1/2 y^3)) ?

The solution to expand ((-10/5 x^4y^3z^2))/((1/2 y^3)) is -4x^4z^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand ((-10/5 x^4y^3z^2))/((1/2 y^3))

expand

\frac{( - \frac{10}{5} x ^{4} y ^{3} z ^{2} )}{( \frac{1}{2} y ^{3} )}

- 4 x^{4} z^{2}

Solution steps

\frac{- \frac{10}{5} x ^{4} y ^{3} z ^{2}}{\frac{1}{2} y ^{3}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{\frac{10}{5} x ^{4} y ^{3} z ^{2}}{\frac{1}{2} y ^{3}}

Multiply

\frac{10}{5} x^{4} y^{3} z^{2} : 2 x^{4} y^{3} z^{2}

= - \frac{2 x ^{4} y ^{3} z ^{2}}{\frac{1}{2} y ^{3}}

Multiply

\frac{1}{2} y^{3} : \frac{y ^{3}}{2}

= - \frac{2 x ^{4} y ^{3} z ^{2}}{\frac{y ^{3}}{2}}

Simplify

\frac{2 x ^{4} y ^{3} z ^{2}}{\frac{y ^{3}}{2}} : \frac{4 x ^{4} y ^{3} z ^{2}}{y ^{3}}

= - \frac{4 x ^{4} y ^{3} z ^{2}}{y ^{3}}

Cancel the common factor:

y^{3}

= - 4 x^{4} z^{2}

(\frac{- 21}{34} - \frac{16 x}{- 17})^{2}

(x^{2} + x + 1) (- 15 x^{2} + 15 x - \frac{3}{2})

11 z (- z + 11)

(- \frac{2}{9} x - \frac{1}{3}) (2 x - 3)

\frac{x + 16}{x ^{2} ( x ^{2} + 4 )}

What is expand ((-10/5 x^4y^3z^2))/((1/2 y^3)) ?
The solution to expand ((-10/5 x^4y^3z^2))/((1/2 y^3)) is -4x^4z^2