What is expand (3x^2-4)(x^3-4x)^{1/2} ?

The solution to expand (3x^2-4)(x^3-4x)^{1/2} is (x^3-4x)^{1/2}*3x^2-(x^3-4x)^{1/2}*4

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expand (3x^2-4)(x^3-4x)^{1/2}

expand

(3 x^{2} - 4) (x^{3} - 4 x)^{\frac{1}{2}}

(x^{3} - 4 x)^{\frac{1}{2}} \cdot 3 x^{2} - (x^{3} - 4 x)^{\frac{1}{2}} \cdot 4

Solution steps

(3 x^{2} - 4) (x^{3} - 4 x)^{\frac{1}{2}}

= (x^{3} - 4 x)^{\frac{1}{2}} (3 x^{2} - 4)

Apply the distributive law:

a (b - c) = ab - a c

(x^{3} - 4 x)^{\frac{1}{2}} (3 x^{2} - 4) = (x^{3} - 4 x)^{\frac{1}{2}} \cdot 3 x^{2} - (x^{3} - 4 x)^{\frac{1}{2}} \cdot 4

= (x^{3} - 4 x)^{\frac{1}{2}} \cdot 3 x^{2} - (x^{3} - 4 x)^{\frac{1}{2}} \cdot 4

(a - 2 x) \cdot (3 a + x)

- sin (x) \cdot (sin (x) - k)

\frac{( 3 s ^{2} + 20 )}{( ( s + 4 ) s ^{2} + 1 )}

\frac{7}{( x + 2 ) ( x - 2 )}

\frac{2 ( X - 3 )}{3}

What is expand (3x^2-4)(x^3-4x)^{1/2} ?
The solution to expand (3x^2-4)(x^3-4x)^{1/2} is (x^3-4x)^{1/2}*3x^2-(x^3-4x)^{1/2}*4