What is expand ((x-2)(x+1))/((x-5)(x-1)) ?

The solution to expand ((x-2)(x+1))/((x-5)(x-1)) is (x^2-x-2)/(x^2-6x+5)

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expand ((x-2)(x+1))/((x-5)(x-1))

expand

\frac{( x - 2 ) ( x + 1 )}{( x - 5 ) ( x - 1 )}

\frac{x ^{2} - x - 2}{x ^{2} - 6 x + 5}

Solution steps

\frac{( x - 2 ) ( x + 1 )}{( x - 5 ) ( x - 1 )}

Expand

(x - 5) (x - 1) : x^{2} - 6 x + 5

= \frac{( x - 2 ) ( x + 1 )}{x ^{2} - 6 x + 5}

Expand

(x - 2) (x + 1) : x^{2} - x - 2

= \frac{x ^{2} - x - 2}{x ^{2} - 6 x + 5}

(1 - sin^{2} (x))^{2}

(x - 4)^{4}

0.03 \cdot 1 (1. 2^{1})

(5 x^{2} - 4) (5 w^{2} - \frac{3}{2})

(x - 7) (x - 6)^{8} ln (\frac{x}{5})

What is expand ((x-2)(x+1))/((x-5)(x-1)) ?
The solution to expand ((x-2)(x+1))/((x-5)(x-1)) is (x^2-x-2)/(x^2-6x+5)