What is expand (-3x^2-3x+27)/((x+2)(2x^2+3x-9)) ?

The solution to expand (-3x^2-3x+27)/((x+2)(2x^2+3x-9)) is (-3x^2-3x+27)/(2x^3+7x^2-3x-18)

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expand (-3x^2-3x+27)/((x+2)(2x^2+3x-9))

expand

\frac{- 3 x ^{2} - 3 x + 27}{( x + 2 ) ( 2 x ^{2} + 3 x - 9 )}

\frac{- 3 x ^{2} - 3 x + 27}{2 x ^{3} + 7 x ^{2} - 3 x - 18}

Solution steps

\frac{- 3 x ^{2} - 3 x + 27}{( x + 2 ) ( 2 x ^{2} + 3 x - 9 )}

Expand

(x + 2) (2 x^{2} + 3 x - 9) : 2 x^{3} + 7 x^{2} - 3 x - 18

= \frac{- 3 x ^{2} - 3 x + 27}{2 x ^{3} + 7 x ^{2} - 3 x - 18}

N e^{3 x} \cdot 3 + M e^{x} + G (e^{x} + e^{x} x)

(1 - cot (x)) (1 + cos (x))

(\frac{80 x}{20} = \frac{x z}{30} + \frac{x y}{30}) (20) (30)

(x - 6) (x - 2)

5 (3 - 10)

What is expand (-3x^2-3x+27)/((x+2)(2x^2+3x-9)) ?
The solution to expand (-3x^2-3x+27)/((x+2)(2x^2+3x-9)) is (-3x^2-3x+27)/(2x^3+7x^2-3x-18)