What is expand (2(k^3+3k^2+5k+2))/3 ?

The solution to expand (2(k^3+3k^2+5k+2))/3 is (2k^3)/3+2k^2+(10k)/3+4/3

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expand (2(k^3+3k^2+5k+2))/3

expand

\frac{2 ( k ^{3} + 3 k ^{2} + 5 k + 2 )}{3}

\frac{2 k ^{3}}{3} + 2 k^{2} + \frac{10 k}{3} + \frac{4}{3}

Solution steps

\frac{2 ( k ^{3} + 3 k ^{2} + 5 k + 2 )}{3}

Expand

2 (k^{3} + 3 k^{2} + 5 k + 2) : 2 k^{3} + 6 k^{2} + 10 k + 4

= \frac{2 k ^{3} + 6 k ^{2} + 10 k + 4}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{2 k ^{3} + 6 k ^{2} + 10 k + 4}{3} = \frac{2 k ^{3}}{3} + \frac{6 k ^{2}}{3} + \frac{10 k}{3} + \frac{4}{3}

= \frac{2 k ^{3}}{3} + \frac{6 k ^{2}}{3} + \frac{10 k}{3} + \frac{4}{3}

Divide the numbers:

\frac{6}{3} = 2

= \frac{2 k ^{3}}{3} + 2 k^{2} + \frac{10 k}{3} + \frac{4}{3}

\frac{sec ( 2 ( x + y ) ) - sec ( 2 x )}{y}

\frac{3 e ^{83}}{16} (x - 64)

(x - 6) (x - 4)

(2 sech^{2} (x)) (1 - 2 tanh (x))

\frac{2 x ^{2} + 4 x + 2}{( x - 3 ) ( x + 2 )}

What is expand (2(k^3+3k^2+5k+2))/3 ?
The solution to expand (2(k^3+3k^2+5k+2))/3 is (2k^3)/3+2k^2+(10k)/3+4/3