What is expand (1+2sin(t))(2cos(t)) ?

The solution to expand (1+2sin(t))(2cos(t)) is 2cos(t)+4cos(t)sin(t)

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expand (1+2sin(t))(2cos(t))

expand

(1 + 2 sin (t)) (2 cos (t))

2 cos (t) + 4 cos (t) sin (t)

Solution steps

(1 + 2 sin (t)) (2 cos (t))

= (2 cos (t)) (1 + 2 sin (t))

Apply the distributive law:

a (b + c) = ab + a c

(2 cos (t)) (1 + 2 sin (t)) = 2 cos (t) \cdot 1 + 2 cos (t) \cdot 2 sin (t)

= 2 cos (t) \cdot 1 + 2 cos (t) \cdot 2 sin (t)

Simplify

2 cos (t) \cdot 1 + 2 cos (t) \cdot 2 sin (t) : 2 cos (t) + 4 cos (t) sin (t)

= 2 cos (t) + 4 cos (t) sin (t)

30.412 (x - 5) (\frac{x - 5}{2} + 5)

e^{x^{2} + 1} \cdot (1 + 2 \cdot x^{2})

\frac{n ^{2} ( n - 1 ) ^{2}}{2}

(5 x + 32 y) 2

10 (\frac{1}{5} v - \frac{3}{2})

What is expand (1+2sin(t))(2cos(t)) ?
The solution to expand (1+2sin(t))(2cos(t)) is 2cos(t)+4cos(t)sin(t)