What is ((x^4)/3-(y^2)/4)((x^4)/3+(y^2)/4) ?

The solution to ((x^4)/3-(y^2)/4)((x^4)/3+(y^2)/4) is ((4x^4-3y^2)(4x^4+3y^2))/(144)

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simplify ((x^4)/3-(y^2)/4)((x^4)/3+(y^2)/4)

simplify

(\frac{x ^{4}}{3} - \frac{y ^{2}}{4}) (\frac{x ^{4}}{3} + \frac{y ^{2}}{4})

\frac{( 4 x ^{4} - 3 y ^{2} ) ( 4 x ^{4} + 3 y ^{2} )}{144}

Solution steps

(\frac{x ^{4}}{3} - \frac{y ^{2}}{4}) (\frac{x ^{4}}{3} + \frac{y ^{2}}{4})

Simplify

\frac{x ^{4}}{3} - \frac{y ^{2}}{4} : \frac{4 x ^{4} - 3 y ^{2}}{12}

= \frac{4 x ^{4} - 3 y ^{2}}{12} (\frac{x ^{4}}{3} + \frac{y ^{2}}{4})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 4 x ^{4} - 3 y ^{2} ) ( \frac{x ^{4}}{3} + \frac{y ^{2}}{4} )}{12}

Simplify

(4 x^{4} - 3 y^{2}) (\frac{x ^{4}}{3} + \frac{y ^{2}}{4}) : \frac{( 4 x ^{4} - 3 y ^{2} ) ( x ^{4} \cdot 4 + y ^{2} \cdot 3 )}{12}

= \frac{\frac{( 4 x ^{4} - 3 y ^{2} ) ( x ^{4} \cdot 4 + y ^{2} \cdot 3 )}{12}}{12}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 4 x ^{4} - 3 y ^{2} ) ( x ^{4} \cdot 4 + y ^{2} \cdot 3 )}{12 \cdot 12}

Multiply the numbers:

12 \cdot 12 = 144

= \frac{( 4 x ^{4} - 3 y ^{2} ) ( x ^{4} \cdot 4 + y ^{2} \cdot 3 )}{144}

= \frac{( 4 x ^{4} - 3 y ^{2} ) ( 4 x ^{4} + 3 y ^{2} )}{144}

(x - (- 2 + i)) (x - (- 2 - i))

(\frac{6}{s ^{3}} - \frac{1}{s + 1}) (1 + \frac{1}{s - 1})

- \frac{40 ( - 34 x ^{4} - 343 x ^{2} - 208 )}{( x ^{2} - 16 ) ^{11}}

\frac{4 ( 3 x ^{2} ( 3 y ^{2} + 1 ) ^{2} - 24 x ^{6} y )}{( 3 y ^{2} + 1 ) ^{3}}

10 (5 - 5)

What is ((x^4)/3-(y^2)/4)((x^4)/3+(y^2)/4) ?
The solution to ((x^4)/3-(y^2)/4)((x^4)/3+(y^2)/4) is ((4x^4-3y^2)(4x^4+3y^2))/(144)