What is expand (2x-5)/((x-4)(x+3)) ?

The solution to expand (2x-5)/((x-4)(x+3)) is (2x-5)/(x^2-x-12)

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expand (2x-5)/((x-4)(x+3))

expand

\frac{2 x - 5}{( x - 4 ) ( x + 3 )}

\frac{2 x - 5}{x ^{2} - x - 12}

Solution steps

\frac{2 x - 5}{( x - 4 ) ( x + 3 )}

Expand

(x - 4) (x + 3) : x^{2} - x - 12

= \frac{2 x - 5}{x ^{2} - x - 12}

\frac{( 5 ( cos ( x ) - 1 ) ( e ^{2} x - 1 ) )}{3 ( e ^{x} + 1 ) x ^{3}}

(x + 3 x^{2}) sin (x)

(x + 2) \cdot (x + 3)

r (t) (t cos (t) -, t) i + (t, t + cos (t)) j + t^{2} k

(5)^{3}

What is expand (2x-5)/((x-4)(x+3)) ?
The solution to expand (2x-5)/((x-4)(x+3)) is (2x-5)/(x^2-x-12)