What is expand (x^2}{4pi}+\frac{(4-x)^2)/4 ?

The solution to expand (x^2}{4pi}+\frac{(4-x)^2)/4 is (x^2}{4pi}+4-2x+\frac{x^2)/4

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expand (x^2}{4pi}+\frac{(4-x)^2)/4

expand

\frac{x ^{2}}{4 π} + \frac{( 4 - x ) ^{2}}{4}

\frac{x ^{2}}{4 π} + 4 - 2 x + \frac{x ^{2}}{4}

Solution steps

\frac{x ^{2}}{4 π} + \frac{( 4 - x ) ^{2}}{4}

(4 - x)^{2} = 16 - 8 x + x^{2}

= \frac{x ^{2}}{4 π} + \frac{x ^{2} - 8 x + 16}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 - 8 x + x ^{2}}{4} = \frac{16}{4} - \frac{8 x}{4} + \frac{x ^{2}}{4}

= \frac{x ^{2}}{4 π} + \frac{16}{4} - \frac{8 x}{4} + \frac{x ^{2}}{4}

Divide the numbers:

\frac{16}{4} = 4

= \frac{x ^{2}}{4 π} + 4 - \frac{8 x}{4} + \frac{x ^{2}}{4}

Divide the numbers:

\frac{8}{4} = 2

= \frac{x ^{2}}{4 π} + 4 - 2 x + \frac{x ^{2}}{4}

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What is expand (x^2}{4pi}+\frac{(4-x)^2)/4 ?
The solution to expand (x^2}{4pi}+\frac{(4-x)^2)/4 is (x^2}{4pi}+4-2x+\frac{x^2)/4