What is expand-((x-1)(10x^2-30x-63))/(10) ?

The solution to expand-((x-1)(10x^2-30x-63))/(10) is -x^3+4x^2+(33x)/(10)-63/10

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expand-((x-1)(10x^2-30x-63))/(10)

expand

- \frac{( x - 1 ) ( 10 x ^{2} - 30 x - 63 )}{10}

- x^{3} + 4 x^{2} + \frac{33 x}{10} - \frac{63}{10}

Solution steps

- \frac{( x - 1 ) ( 10 x ^{2} - 30 x - 63 )}{10}

Expand

(x - 1) (10 x^{2} - 30 x - 63) : 10 x^{3} - 40 x^{2} - 33 x + 63

= - \frac{10 x ^{3} - 40 x ^{2} - 33 x + 63}{10}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{10 x ^{3} - 40 x ^{2} - 33 x + 63}{10} = - (\frac{10 x ^{3}}{10}) - (- \frac{40 x ^{2}}{10}) - (- \frac{33 x}{10}) - (\frac{63}{10})

= - (\frac{10 x ^{3}}{10}) - (- \frac{40 x ^{2}}{10}) - (- \frac{33 x}{10}) - (\frac{63}{10})

Remove parentheses:

(a) = a, - (- a) = a

= - \frac{10 x ^{3}}{10} + \frac{40 x ^{2}}{10} + \frac{33 x}{10} - \frac{63}{10}

Divide the numbers:

\frac{10}{10} = 1

= - x^{3} + \frac{40 x ^{2}}{10} + \frac{33 x}{10} - \frac{63}{10}

Divide the numbers:

\frac{40}{10} = 4

= - x^{3} + 4 x^{2} + \frac{33 x}{10} - \frac{63}{10}

(2 - 4 i)^{8}

sec (a) (sec (a) + tan (a))

2 \cdot π (x + y)

\frac{( s + 1 ) ^{2} + 1}{( s + 2 ) ( s + 1 ) ^{2}}

x (3 x - 10) - 31 + 1

What is expand-((x-1)(10x^2-30x-63))/(10) ?
The solution to expand-((x-1)(10x^2-30x-63))/(10) is -x^3+4x^2+(33x)/(10)-63/10