What is -x^2-2x+3>= 0 ?

The solution to -x^2-2x+3>= 0 is -3<= x<= 1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-x^2-2x+3>= 0

- x^{2} - 2 x + 3 \geq 0

- 3 \leq x \leq 1

Interval Notation

[- 3, 1]

Solution steps

- x^{2} - 2 x + 3 \geq 0

Factor

- x^{2} - 2 x + 3 : - (x - 1) (x + 3)

- (x - 1) (x + 3) \geq 0

Multiply both sides by

- 1

(reverse the inequality)

(- (x - 1) (x + 3)) (- 1) \leq 0 \cdot (- 1)

Simplify

(x - 1) (x + 3) \leq 0

Identify the intervals

- 3 \leq x \leq 1

b^{2} - 2 b - 35 = 0

(2)^{5}

\frac{3}{8} - \frac{1}{2}

2 x^{2} + 4 x = 48

- 10 x - 5 = - 8 x + 11