What is (3x^2+x+3\circ x+4)(-1) ?

The solution to (3x^2+x+3\circ x+4)(-1) is -3x^2-x-3\circ x-4

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simplify (3x^2+x+3\circ x+4)(-1)

simplify

(3 x^{2} + x + 3 \circ x + 4) (- 1)

- 3 x^{2} - x - 3 \circ x - 4

Solution steps

(3 x^{2} + x + 3 \circ x + 4) (- 1)

Remove parentheses:

(- a) = - a

= - (3 x^{2} + x + 3 \circ x + 4) \cdot 1

Multiply:

(3 x^{2} + x + 3 \circ x + 4) \cdot 1 = (3 x^{2} + x + 3 \circ x + 4)

= - (3 x^{2} + x + 3 \circ x + 4)

Distribute parentheses

= - (3 x^{2}) - (x) - (3 \circ x) - (4)

Apply minus-plus rules

+ (- a) = - a

= - 3 x^{2} - x - 3 \circ x - 4

- 10 (52 - 8)

(cos (\frac{2 π}{9}) - cos (x))^{2} + (sin (\frac{2 π}{9}) - sin (x))^{2}

(y - \frac{3}{2} x) (y - \frac{1}{2} x) (y - \frac{2}{15} x)

\frac{t ^{4} + 1 ( t - 1 )}{t ( t ^{2} - 2 )}

(2 x - 5 y + 2) d x + (1 - 5 x - 6 y) d y

What is (3x^2+x+3\circ x+4)(-1) ?
The solution to (3x^2+x+3\circ x+4)(-1) is -3x^2-x-3\circ x-4