What is expand 2((-2x+2)(2x^2-1)) ?

The solution to expand 2((-2x+2)(2x^2-1)) is -8x^3+8x^2+4x-4

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expand 2((-2x+2)(2x^2-1))

expand

2 ((- 2 x + 2) (2 x^{2} - 1))

- 8 x^{3} + 8 x^{2} + 4 x - 4

Solution steps

2 ((- 2 x + 2) (2 x^{2} - 1))

Remove parentheses:

(a) = a

= 2 (- 2 x + 2) (2 x^{2} - 1)

Expand

(- 2 x + 2) (2 x^{2} - 1) : - 4 x^{3} + 2 x + 4 x^{2} - 2

= 2 (- 4 x^{3} + 2 x + 4 x^{2} - 2)

Expand

2 (- 4 x^{3} + 2 x + 4 x^{2} - 2) : - 8 x^{3} + 4 x + 8 x^{2} - 4

= - 8 x^{3} + 4 x + 8 x^{2} - 4

Rewrite in standard form

= - 8 x^{3} + 8 x^{2} + 4 x - 4

sec (x) (1 - sin (2 x))

\frac{x ^{2} - 6 x + 2}{( x - 3 ) ^{2}}

\frac{( x + 2 ) \cdot x ^{2}}{( x - 2 ) ( x - 1 )}

f (\frac{t e ^{a t}}{a} + \frac{- e ^{a t} + 1}{a ^{2}})

(x^{2} - 9) y^{6} + x^{2} y^{'''} (x) + 5 y

What is expand 2((-2x+2)(2x^2-1)) ?
The solution to expand 2((-2x+2)(2x^2-1)) is -8x^3+8x^2+4x-4