What is expand-(2(4e^{pi/2}+4))/pi ?

The solution to expand-(2(4e^{pi/2}+4))/pi is -(8e^{pi/2})/pi-8/pi

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expand-(2(4e^{pi/2}+4))/pi

expand

- \frac{2 ( 4 e ^{\frac{π}{2}} + 4 )}{π}

- \frac{8 e ^{\frac{π}{2}}}{π} - \frac{8}{π}

Solution steps

- \frac{2 ( 4 e ^{\frac{π}{2}} + 4 )}{π}

Expand

2 (4 e^{\frac{π}{2}} + 4) : 8 e^{\frac{π}{2}} + 8

= - \frac{8 e ^{\frac{π}{2}} + 8}{π}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 e ^{\frac{π}{2}} + 8}{π} = - (\frac{8 e ^{\frac{π}{2}}}{π}) - (\frac{8}{π})

= - (\frac{8 e ^{\frac{π}{2}}}{π}) - (\frac{8}{π})

Remove parentheses:

(a) = a

= - \frac{8 e ^{\frac{π}{2}}}{π} - \frac{8}{π}

- {- 5 + 3 x^{3} - [- (\frac{6}{3} + 2)]}

\frac{( ln ( 3 ) + 1 ) ln ( 8 x )}{ln ( 3 x ) + 1}

\frac{( a + s ) ^{2} - b ^{2}}{( a + s ) ^{3}}

A (- 12.23) B (- 11, - 15)

2 sin (a) (cos (3 a) + cos (a))

What is expand-(2(4e^{pi/2}+4))/pi ?
The solution to expand-(2(4e^{pi/2}+4))/pi is -(8e^{pi/2})/pi-8/pi