What is 12(log_{a}(b)+log_{b}(c)) ?

The solution to 12(log_{a}(b)+log_{b}(c)) is 12log_{a}(b)+12log_{b}(c)

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simplify 12(log_{a}(b)+log_{b}(c))

simplify

12 (lo g_{a} (b) + lo g_{b} (c))

12 lo g_{a} (b) + 12 lo g_{b} (c)

Solution steps

12 (lo g_{a} (b) + lo g_{b} (c))

Apply the distributive law:

a (b + c) = ab + a c

12 (lo g_{a} (b) + lo g_{b} (c)) = 12 lo g_{a} (b) + 12 lo g_{b} (c)

= 12 lo g_{a} (b) + 12 lo g_{b} (c)

2^{2} + 3^{2}

\frac{2 ( k + 1 ) ( k + 2 ) ( 2 k + 2 )}{3}

\frac{K ( s ^{2} + 4 s + 8 )}{s ^{3} + s ^{2}}

\frac{( x - 6 ) ^{6}}{x}

\frac{( a - 1 ) ^{2}}{4}

What is 12(log_{a}(b)+log_{b}(c)) ?
The solution to 12(log_{a}(b)+log_{b}(c)) is 12log_{a}(b)+12log_{b}(c)