What is expand (-kc^{k-1}+2c^{k-1})/((k+2)(k+1)) ?

The solution to expand (-kc^{k-1}+2c^{k-1})/((k+2)(k+1)) is (-kc^{k-1}+2c^{k-1})/(k^2+3k+2)

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expand (-kc^{k-1}+2c^{k-1})/((k+2)(k+1))

expand

\frac{- k c ^{k - 1} + 2 c ^{k - 1}}{( k + 2 ) ( k + 1 )}

\frac{- k c ^{k - 1} + 2 c ^{k - 1}}{k ^{2} + 3 k + 2}

Solution steps

\frac{- k c ^{k - 1} + 2 c ^{k - 1}}{( k + 2 ) ( k + 1 )}

Expand

(k + 2) (k + 1) : k^{2} + 3 k + 2

= \frac{- k c ^{k - 1} + 2 c ^{k - 1}}{k ^{2} + 3 k + 2}

\frac{( ( s + π ) e ^{- s} )}{s ^{2} + π ^{2}}

(t^{\frac{1}{2}} x + t^{\frac{1}{3}} y)^{3}

\frac{( 1 - \frac{1}{x ^{3} + 2} )}{( x + \frac{1}{x - 1} )}

(x - 1 + i 2)^{2} \cdot (x + 1 + i 2)^{2}

lo g_{x} (\frac{y}{3 z})

What is expand (-kc^{k-1}+2c^{k-1})/((k+2)(k+1)) ?
The solution to expand (-kc^{k-1}+2c^{k-1})/((k+2)(k+1)) is (-kc^{k-1}+2c^{k-1})/(k^2+3k+2)