What is expand 12((x-4)/4+x/3 = 6/1) ?

The solution to expand 12((x-4)/4+x/3 = 6/1) is 7x-12=6

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expand 12((x-4)/4+x/3 = 6/1)

expand

12 (\frac{x - 4}{4} + \frac{x}{3} = \frac{6}{1})

7 x - 12 = 6

Solution steps

12 (\frac{x - 4}{4} + \frac{x}{3} = \frac{6}{1})

= 12 (\frac{x - 4}{4} + \frac{6}{1} = \frac{x}{3})

Apply the distributive law:

a (b + c) = ab + a c

a = 12, b = \frac{x - 4}{4}, c = \frac{x}{3} = \frac{6}{1}

12 \cdot \frac{x - 4}{4} + 12 \cdot \frac{x}{3} = \frac{6}{1}

Simplify

12 \cdot \frac{x - 4}{4} + 12 \cdot \frac{x}{3} = \frac{6}{1} : 7 x - 12 = 6

7 x - 12 = 6

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What is expand 12((x-4)/4+x/3 = 6/1) ?
The solution to expand 12((x-4)/4+x/3 = 6/1) is 7x-12=6