What is expand e^{t-2}h(t-2) ?

The solution to expand e^{t-2}h(t-2) is e^{t-2}th-2e^{t-2}h

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expand e^{t-2}h(t-2)

expand

e^{t - 2} h (t - 2)

e^{t - 2} t h - 2 e^{t - 2} h

Solution steps

e^{t - 2} h (t - 2)

Apply the distributive law:

a (b - c) = ab - a c

a = e^{t - 2} h, b = t, c = 2

= e^{t - 2} h t - e^{t - 2} h \cdot 2

= e^{t - 2} t h - 2 e^{t - 2} h

(x - 2) (x - 2)

- \frac{s}{2 ( s ^{2} + 8 s + 16 )}

4.9 (5 - \frac{s}{340})^{2}

x^{4} 6 - x (e^{k} - e^{- z})

\frac{2 s ^{2} + 2 s - 1}{s ^{2} ( s ^{2} - 2 s - 1 )}

What is expand e^{t-2}h(t-2) ?
The solution to expand e^{t-2}h(t-2) is e^{t-2}th-2e^{t-2}h